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2 years ago

X3 − 2y2 − 3x3 + z4 if x = 3, y = 5, and z = −3

2 answers:

4 0

X³ - 2y² - 3x³ +z^4
(substitute the values)

3³ - 2(5)² - 3(3)³ + (-3)^4
27 - 10² - 9³ + 81
27 - 100 - 729 + 81
-73 - 648
-721

So, the answer is -721

HOPE THIS HELPS!!!!

Olenka [21]2 years ago

4 0

9 - 10 - 27 + -12 = -40

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Solve each equation:

timurjin [86]

1.) x=-9 because
2.) x=16

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Use the formula for the cosine of the difference of two angles to find the exact value of the following expression.

Zolol [24]

Answer:

Exact value of Cos(45° - 60°) is 0.96 using difference of two angles.

Step-by-step explanation:

Given:

Cos(45° - 60°)

We have to apply the formula of cosine for difference of the two angles.

Formula:

$cos(a-b)=cos(a)\ cos(b)+sin(a)\ sin(b)$

Plugging the values.

⇒ $cos(45-60)=cos(45)\ cos(60) + sin(45)\ sin(60)$

We know that the values :

$sin(45) =cos(45) = \frac{1}{\sqrt{2} }$

$sin(60)=\frac{\sqrt{3} }{2}$ and $cos(60)=\frac{1}{2}$

So,

⇒ $cos(45-60)=(\frac{1}{\sqrt{2} } \times \frac{1}{2} ) + (\frac{1}{\sqrt{2} } \times \frac{\sqrt{3} }{2})$

⇒ $cos(45-60)=(\frac{1}{2\sqrt{2} } + \frac{\sqrt{3} }{2\sqrt{2} })$

⇒ $cos(45-60)=(\frac{1+\sqrt{3} }{2\sqrt{2} } )$

⇒ $cos(45-60)=(\frac{1+\sqrt{3} }{2\sqrt{2} } )\times \frac{2\sqrt{2} }{2\sqrt{2} }$ ...rationalizing

⇒ $cos(45-60)=\frac{2\sqrt{2} +2\sqrt{6} }{ 8}$

⇒ $cos(45-60)=\frac{2(\sqrt{2}+\sqrt{6})}{8}$ ...taking 2 as a common factor

⇒ $cos(45-60)=\frac{(\sqrt{2}+\sqrt{6})}{4}$

To find the exact values we have to put the values of sq-rt .

As, $\sqrt{2}=1.41$ and $\sqrt{6} =2.44$

Then

⇒ $cos(45-60)=\frac{( 1.41+2.44)}{4}$

⇒ $cos(45-60)=\frac{( 3.85)}{4}$

⇒ $cos(45-60)=0.96$

So the exact value of Cos(45° - 60°) is 0.96 using difference of two angles.

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2 years ago

Mrs. Jones decided to buy some pencils for her class. She bought 5 packages of pencils, and each package contained 66 pencils. T

8_murik_8 [283]

D.3 is the correct answer :)

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2 years ago

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42+58=n+60 the answer for this problem

seraphim [82]

The answer is n= 40.

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3 years ago

The volume of an oblique pyramid with a square base is V units3 and the height is h units.

TiliK225 [7]

The volume of a quadrangular base pyramid is:
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An expression that represents the area of the base of the pyramid is:
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2 years ago

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