The answer to “most of the energy released by nuclear fission in the form of _____ rays.” is GAMMA RAYS
The answer is: A) Na3PO4 + 3KOH → 3NaOH + K3PO4, because K retains the same charge throughout the reaction.
This chemical reaction is double displacement reaction - cations (K⁺ and Na⁺) and anions (PO₄³⁻⁻ and OH⁻) of the two reactants switch places and form two new compounds.
Na₃PO₄ is sodium phosphate.
KOH is potassium hydroxide.
NaOH is sodium hydroxide.
K₃PO₄ is potassium phosphate.
According to the mass conservation law, there are same number of atoms on both side of balanced chemical reaction.
Answer:
Easy my dude let me help you out
A.In
B.27
C.73
D.49
E.56
F.56
G.114
H.180
Also with protons and electrons they equal the same atomic number
