Answer: Does not exist.
Step-by-step explanation:
Since, given function, f(x) = 6x tan x, where −π/2 < x < π/2.
⇒ f(x) = 
And, for vertical asymptote, cosx= 0
⇒ x = π/2 + nπ where n is any integer.
But, for any n x is does not exist in the interval ( -π/2, π/2)
Therefore, vertical asymptote of f(x) where −π/2 < x < π/2 does not exist.
Solve. Note the equal sign. What you do to one side, you do to the other. Remember to follow PEMDAS.
First, distribute 5 to all terms within the parenthesis
5(w - 1) = (5)(w) + (5)(-1) = 5w - 5
Next, simplify. Combine like terms
5w - 5 - 2 = 5w + 7
5w - 7 = 5w + 7
Next, isolate the variable. Add 7 to both sides, and subtract 5w from both sides
5w (-5w) - 7 (+7) = 5w (-5w) + 7 (+7)
5w - 5w = 7 + 7
0 = 14 (Untrue).
0 solutions, or (A) is your answer
~<em>Rise Above the Ordinary</em>
Answer:
OK with what
Step-by-step explanation:
OK with what
Simplify the expression
-15x4y3+3x3y2
Hope this helps! :)
~Zain
Set up an algebraic equation: b=cost of ball
1.10=1+b+b
1.10=1+2b
subtract 1 from both sides
.10=2b
divide by 2 on both sides
ball=5 cents
