Give ONE real-life example for CHARLE'S LAW and for BOYLE'S LAW in action.
2 answers:
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Answer:
15.825 m
Explanation:
t = Time taken = 2.5 s
u = Initial velocity = 6.75 m/s
v = Final velocity = 5.91 m/s
s = Displacement
a = Acceleration
Equation of motion
The distance Rickey slides across the ground before touching the base is 15.825 m
Answer:
-1 m/s
Explanation:
From the law of conservation of linear momentum, the sum of initial and final momentum should be equal. Momentum, p is expressed as the product of mass and velocity. Therefore, p=mv where m and v represent mass and velocity respectively. In this case
Where subscripts d and u represent downwards and upwards respectively while c is common hence common velocity which is unknown in this case. Taking downwards as negative while upwards as positive then substituting -3 m/s for downward speed while 3 m/s for upward speed, the masses as given then
(2*-3)+(1*3)=(2+1)v
V=-1 m/s hence downward direction