First thing you should do is reduce coefficients.
1st equation has all multiples of '2'. Divide by 2
---> x +3y = -6
2nd equation has multiples of 5. Divide by 5.
---> x - y = 2
Now elimination part is easier.
Eliminate 'x' variable by subtracting 2nd equation from 1st.
x + 3y = -6
-(x - y = 2)
----------------------
4y = -8
Solve for 'y'
4y = -8
y = (-8)/4 = -2
Substitute value for 'y' back into 2nd equation:
x - (-2) = 2
x + 2 = 2
x = 0
Solution to system is:
x=0, y =-2
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Answer:
Step-by-step explanation:
Given
Required
The area of the garden
First, we calculate the length of the other side using:
This gives:
Divide both sides by 2
Make Side 2 the subject
So, the area of the garden is:
Expand
To solve for y, you need to separate it in one side and the other terms in the other side..... as follows:
<span>a(n+y)=10y+32a
an + ay = 10y + 32a
an - an + ay = 10y + 32a - an
ay = 10y + 32a - an
ay -10y = 32a - an
y (a-10) = (32 - n)a
y = {a(32-n)} / (a-10)
</span>