Solve the system of linear equations using either substitution or the elimination method.
1 answer:
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Solution :
Given :
n = 15
s = 0.5902
The hypothesis :
This is a 2 tailed test.
The significance level is
The test statistic :
= -0.72
The p value : The p value for Z = -0.72 is 0.4716
The critical value : the critical value at α = 0.05 is +1.96 to -1.96
The decision rule :
If or if
, then reject
.
Also if p value is less than α, then reject .
The decision :
Since the Z falls in between +1.96 and -1.96, we fail to reject the . Also since p value is greater than α, we fail to reject
.
The conclusion :
There is not sufficient evidence at the 95% significance level to warrant rejection of the claim that the pills come from a population in which the amount of the atorvastatin is equal to 25 mg.
Now calculating the mean and the standard deviation :
Standard deviation =
Variance =
Where, SS =
X Mean
24.1 24.89 0.62
24.4 24.89 0.24
24.3 24.89 0.35
24.9 24.89 0
24.1 24.89 0.62
24.2 24.89 1.72
24.1 24.89 0.04
26.2 24.89 0.04
25.1 24.89 0.24
25 24.89 0.01
24.7 24.89 0.04
25.1 24.89 0.04
25.3 24.89 0.17
25.5 24.89 0.37
25.5 24.89 0.37
n 15
Sum 373.3
Average 24.89
SS 4.8775
Variance = 0.348392857
Standard deviation 0.5902