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2 years ago

Variable Terms in 3x + 2 – 10 – 3x

Mathematics

1 answer:

ratelena [41]2 years ago

6 0

Answer:

Step-by-step explanation:

because its the varible term

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How do you simplify this? x²y+xy² / y²+2/5 × xy

polet [3.4K]

$\huge \boxed{\mathbb{QUESTION} \downarrow}$

How do you simplify this?
x²y+xy² / y²+2/5 × xy

$\large \boxed{\mathbb{ANSWER\: WITH\: EXPLANATION} \downarrow}$

$\sf\frac{ { x }^{ 2 } y+x { y }^{ 2 } }{ { y }^{ 2 } + \frac{ 2 }{ 5 } \times xy } \\$

Factor the expressions that are not already factored.

_____

How to factorise :-

NUMERATOR $\downarrow$

$\sf \: x ^ { 2 } y + x y ^ { 2 }$

Factor out xy.

$\sf \: xy\left(x+y\right)$

DENOMINATOR $\downarrow$

$\sf{ y }^{ 2 } + \frac{ 2 }{ 5 } \times xy \\$

Factor out 1/5.

$\sf \: {\frac{1}{5}y\left(2x+5y\right)} \\$

_____

Continuing...

$\sf\frac{xy\left(x+y\right)}{\frac{1}{5}y\left(2x+5y\right)} \\$

Cancel out y in both the numerator and denominator.

$\sf\frac{x\left(x+y\right)}{\frac{1}{5}\left(2x+5y\right)} \\$

Expand the expression.

$\sf\frac{x^{2}+xy}{\frac{2}{5}x+y} \\$

This can further simplified to as $\downarrow$

$= \boxed{\boxed{\bf\frac{5x\left(x +y\right)}{2x+5y}}}$

3 0

2 years ago

Melissa's service charge at a beauty salon

satela [25.4K]

Answer:

melissa pays 18.144

Step-by-step explanation:

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2 years ago

If both diagonals of a quadrilateral bisect each other when is the quadrilateral a parallelogram?

slamgirl [31]

It is more than just a quadrilateral. In fact it is going to be hard to pick.

These facts suit a square, a rectangle, a rhombus, and a parallelogram. And the above statement is true, but maybe a little harder to prove than the converse of the statement, which is the usual one you find.

The converse is "If you have a parallelagram, the diagonals bisect each other."

You might think a trapezoid deserves some mention. The diagonals of a trapezoid do not bisect each other.

6 0

2 years ago

Help pls reallyyyyyyyyyyyyyyyyyy

Ivan

Answer:

Step-by-step explanation:

j=6

k=4

Rewrite the equation. So let's do that-

2.5(6*4)/6

6 and the other 6 cancel out so we are left with 2.5*4

Which is then equal to 10.

By the way, whenever you see the same number in a division problem on the numerator and denominator, just cancel them out because if you still did 2.5(6*4)/6, you would still get 10. I was just simplifying it!

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2 years ago

Factorise fully the following: a) x² - 2x b) 6x^2+ 12x c) 3x^3- 9x d) 4x^2+ 28x^3

mezya [45]

Answer:

a) x(x - 2)

b) 6x(x + 2)

c) 3x(x^2-3)

d) (2x)(2x)(1+7x)

Step-by-step explanation:

8 0

2 years ago