Answer:
1. 35
2. 145
3. 55
4. 125
5. 55
13. x= 19
Step-by-step explanation:
Answer:
The distance between the ship at N 25°E and the lighthouse would be 7.26 miles.
Step-by-step explanation:
The question is incomplete. The complete question should be
The bearing of a lighthouse from a ship is N 37° E. The ship sails 2.5 miles further towards the south. The new bearing is N 25°E. What is the distance between the lighthouse and the ship at the new location?
Given the initial bearing of a lighthouse from the ship is N 37° E. So, is 37°. We can see from the diagram that would be 143°.
Also, the new bearing is N 25°E. So, would be 25°.
Now we can find . As the sum of the internal angle of a triangle is 180°.
Also, it was given that ship sails 2.5 miles from N 37° E to N 25°E. We can see from the diagram that this distance would be our BC.
And let us assume the distance between the lighthouse and the ship at N 25°E is
We can apply the sine rule now.
So, the distance between the ship at N 25°E and the lighthouse is 7.26 miles.
9514 1404 393
Answer:
255
Step-by-step explanation:
If the sum of digits is 12, the number is divisible by 3. If the number ends in 0 or 5, it is divisible by 5. So, we're looking for ...
2x0 . . . where x is a digit and 2+x+0 = 12 . . . . . . not possible
2x5 . . . where x is a digit and 2+x+5 = 12 . . . . true for x=5
The number is 255.
The answer is 24/35. i would tell you to simplify but it is already in its simpliest form.
The answer is <span>D.∠3
If you use a proctor you can see they measure the same
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