The volume of the gas increases as the temperature increases. As temperature increases, the molecules of the gas have more kinetic energy. They strike the surface of the container with more force. If the container can expand, then the volume increases until the pressure returns to its original value. I hope that helped!!
The concentration of the solution decreases hence the time taken for the cross to become invisible increases.
<h3>Rate of reaction</h3>
The term rate of reaction refers to how quickly or slowly a reaction occurs. This is usually measured in units of time. We are now going to look at the scenario in the question.
We know that rate of reaction depends on the concentration of the reactants. The higher the concentration, the more the reacting particles in solution and the faster the rate of reaction.
As the volume of thiosulphate decreases and the volume of water increases, the concentration of the solution decreases hence the time taken for the cross to become invisible increases.
Learn more about rate of reaction: brainly.com/question/8592296
Answer:
pOH = 8.9
Explanation:
pOH+pH = 14
pH= 14- pOH
pOH = 8.9, pH=14-8.9 = 5.1
pOH = 5.5, pH=14-5.5 = 8.5
Than less pH , than more H+ ion concentration.
pH=5.1 <pH=8.5
pH=5.1 is more acidic solution
pH=5.1 or pOH=8.9 has a higher H+ concentration.
Answer:
13.5 * 10^-2 g
Explanation:
What we know:
Balanced Equation: 3Ba+Al2(SO4)3 -->2Al+3BaSO4,
Grams of Ba: 1
Grams of Al2(SO4)3: 1.8g
Calculate the # of moles of Ba and Al2(SO4)3:
1g Ba/137.3 = 7.3 *10^-3 mol Ba
1.8g Al2(SO4)3/ 342 = 5.3 *10^-3 mol Al2(SO4)3
Find the limiting reactant:
Ba has a coefficient of 3 in the balanced equation, so we divide the # of moles of Ba by 3 to get... 7.3 *10^-3 mol Ba/3 = 2.43 *10^-3
Al2(SO4)3 has a coefficient of 1, so if we divide by 1, we get the same number of 5.3 *10^-3
2.43 *10^-3 is smaller than 5.3 *10^-3, therefore Ba is the limiting reactant.
finally, we just find the number of moles of Al
The ratio of Al to Ba is 2:3 so...
7.3 * 10^-3 * (2/3) = 5 *10^-3 mol Al
CONVERT TO GRAMS
5 *10^-3 mol Al * 27 = 13.5 * 10^-2 g
<u>Hope that was helpful! </u>
Answer:
0.055g/mL
Explanation:
Data obtained from the question include:
Molar Mass of the gass sample = 71g/mol
Volume of the gas sample = 1300 mL
Density =?
The density of a substance is simply mass per unit volume. It is represented mathematically as:
Density = Mass /volume.
With the above equation, we can easily obtain the density of sample of gas as illustrated below:
Density = 71g / 1300 mL
Density = 0.055g/mL
Therefore, the density of the gas sample is 0.055g/mL
