Find the measure of the missing angles in the kite

Mathematics

1 answer:

frutty [35]2 years ago

5 0

Answer: 360 - 44 - 80 = 236

236 ÷ 2 = 118

both angle equal to 118

Step-by-step explanation:

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give the length and width in whole inches of three different rectangles that each have an area of 48 in. squared

lozanna [386]

To find the length and width of 3 different rectangles that have an area of 48 square inches, you can use the factor pairs that result in 48.

The reason is that to find the area of a rectangle you multiply two dimensions.

2 in x 12 in
3 in x 8 in
4 in x 6 in

On all these either one could be the length and the other the width.

8 0

2 years ago

F(t)=t^2+19t+60<br> What are the zeros of the function and what is the vertex of the parabola?

SVEN [57.7K]

Answer: $-4,-15;\ \left(-\dfrac{19}{2},-\dfrac{121}{4}\right)$

Step-by-step explanation:

Given

Function is $F(t)=t^2+19+60$

Zeroes of the function are

$t^2+19t+60=0\\\\\Rightarrow t=\dfrac{-19\pm\sqrt{19^2-4\times 1\times 60}}{2\times 1}\\\\\Rightarrow t=\dfrac{-19\pm \sqrt{121}}{2}\\\\\Rightarrow t=\dfrac{-19\pm 11}{2}\\\\\Rightarrow t=-4,-15$

Using completing the square method

$y=t^2+2\times \dfrac{19}{2}t+\dfrac{19^2}{2^2}-\dfrac{19^2}{2^2}+60\\\\y=\left(t+\dfrac{19}{2}\right)^2+60-\dfrac{361}{4}\\\\y=\left(t+\dfrac{19}{2}\right)^2-\dfrac{121}{4}\\\\y+\dfrac{121}{4}=\left(t+\dfrac{19}{2}\right)^2\\\\\left(y-(-\dfrac{121}{4}\right)=\left(t-(-\dfrac{19}{2})\right)^2\\\\\text{The vertex is }\left(-\dfrac{19}{2},-\dfrac{121}{4}\right)$