Answer:
Step-by-step explanation:
we have the ratio
To write as percent, multiply the ratio by 100
so
Answer:
it's answer is C. 1
Step-by-step explanation:
Given
f(x) = -2x + 7
f(3) = - 2 * 3 + 7
= - 6 + 7
= 1
Answer:
From your question, I am assuming you are talking about an absolute value graph. In this case the answer would be y = |2 + 6|
Step-by-step explanation: Always remember, when you are graphing absolute value graphs:
When you shift left or right, you put the amount you are shifting inside the absolute value sign.
When you are shifting up or down, you put the amount you are shifting outside the absolute value sign.
When shifting left on a graph, you usually think of subtraction. However, when dealing with absolute value graphs, when you are shifting left, you use addition, as you can see in this problem.
The same goes for right. You use subtraction when shifting right, contrary to what you may think.
However, when you go up, you still use addition, and when you shift down, you still use subtraction.
Using the <em>normal distribution and the central limit theorem</em>, it is found that there is a 0.1335 = 13.35% probability that 100 randomly selected students will have a mean SAT II Math score greater than 670.
<h3>Normal Probability Distribution</h3>
In a normal distribution with mean and standard deviation , the z-score of a measure X is given by:
- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
- By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation .
In this problem:
- The mean is of 660, hence .
- The standard deviation is of 90, hence .
- A sample of 100 is taken, hence .
The probability that 100 randomly selected students will have a mean SAT II Math score greater than 670 is <u>1 subtracted by the p-value of Z when X = 670</u>, hence:
By the Central Limit Theorem
has a p-value of 0.8665.
1 - 0.8665 = 0.1335.
0.1335 = 13.35% probability that 100 randomly selected students will have a mean SAT II Math score greater than 670.
To learn more about the <em>normal distribution and the central limit theorem</em>, you can take a look at brainly.com/question/24663213
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