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2 years ago

The base of the pyramid is a square of side 12cm.

Mathematics

1 answer:

atroni [7]2 years ago

5 0

Answer:

384 .cm2

Step-by-step explanation:

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The perimeter of a rectangular field is 362 m. If the width of the field is 83 m, what is it’s length?

Doss [256]

83+83+2x=362
166+2x=362
2x=196
length = 98

6716÷92=73
width = 73

4 0

2 years ago

Find f^-1 (12) if x f(x)=3x-7

saveliy_v [14]

Answer:

The value of $f^{-1}(12)$ is $\frac{7}{-9}$ .

Step-by-step explanation:

The given equation is $x f(x) = 3x-7$ .

$f(x)=3-\frac{7}{x}$

The inverse of the function is found by adjusting the equation such that, expressing x in terms of f(x).

$\frac{7}{x} = 3 - f(x)$

$x = \frac{7}{3-f(x)}$

now, x = $f^{-1}(x)$ and f(x) be x.

Thus, $f^{-1}(x) = \frac{7}{3-x}$

Now, inserting value of x as 12,

$f^{-1}(12) = \frac{7}{3-(12)}$

$f^{-1}(12) = \frac{7}{-9}$

8 0

2 years ago

Read 2 more answers

Define a new random variable by y = 2px. show that, as p l 0, the mgf of y converges to that of a chi squared random variable wi

Mandarinka [93]

The moment generating function (mgf) of y is given by

$M_y(t)=E(e^{ty})=E(e^{2pxt})=M_x(2pt)=p(1-e^{2pt}(1-p))^{-1}$

Since the momoent generating function of x is given by $M_x(t)=p(1-e^{t}(1-p))^{-1}$

When p tends to 0, we have

$\lim_{p \to 0} M_y(t)= \lim_{p \to 0} \frac{p}{1-e^{2pt}(1-p)} = \frac{0}{0}$

Applying L'Hopital's rule we have:

$\lim_{p \to 0} M_y(t)=\lim_{p \to 0} \frac{1}{e^{2pt}+2te^{2pt}+2pte^{2pt}} = \frac{1}{1+2t} , \ \ \ t\ \textless \ \frac{1}{2}$

This shows that y converges to a chi squared random variable with 2r degrees of freedom.

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2 years ago

Please help asap 10points!! thanks in advanced!!

denis-greek [22]

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2 years ago

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dimaraw [331]

Answer:

Step-by-step explanation:

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2 years ago