Answer:
Step-by-step explanation:
<u>Eigenvalues of a Matrix</u>
Given a matrix A, the eigenvalues of A, called 
are scalars who comply with the relation:
Where I is the identity matrix
![I=\left[\begin{array}{cc}1&0\\0&1\end{array}\right]](https://tex.z-dn.net/?f=I%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%260%5C%5C0%261%5Cend%7Barray%7D%5Cright%5D)
The matrix is given as
![A=\left[\begin{array}{cc}3&5\\8&0\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D3%265%5C%5C8%260%5Cend%7Barray%7D%5Cright%5D)
Set up the equation to solve
![det\left(\left[\begin{array}{cc}3&5\\8&0\end{array}\right]-\left[\begin{array}{cc}\lambda&0\\0&\lambda \end{array}\right]\right)=0](https://tex.z-dn.net/?f=det%5Cleft%28%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D3%265%5C%5C8%260%5Cend%7Barray%7D%5Cright%5D-%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D%5Clambda%260%5C%5C0%26%5Clambda%20%5Cend%7Barray%7D%5Cright%5D%5Cright%29%3D0)
Expanding the determinant
![det\left(\left[\begin{array}{cc}3-\lambda&5\\8&-\lambda\end{array}\right]\right)=0](https://tex.z-dn.net/?f=det%5Cleft%28%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D3-%5Clambda%265%5C%5C8%26-%5Clambda%5Cend%7Barray%7D%5Cright%5D%5Cright%29%3D0)
Operating Rearranging
Factoring
Solving, we have the eigenvalues
Answer:domain 4 range 6
Step-by-step explanation:
Answer:
18? i don't think it's right but i tried mental math
Step-by-step explanation:
PEMDAS
Answer:
B: 25%
Step-by-step explanation:
$90.00 - $67.50 = $22.5
$22.5 / $90 = 0.25 = 25%
Answer:
B: 25%
The perimeter is the total of adding all of the side lengths together.
A square has 4 equal side lengths.
So the perimeter of a square is:
P = s + s + s + s or P = 4s
[P = perimeter s = side lengths of the square]
Since you know the side length of the square is (x + 2 1/4), you can replace s with (x + 2 1/4)
P = 4s
P = 4(x + 2 1/4) Multiply 4 into (x + 2 1/4)
P = 4x + 8 4/4
P = 4x + 9
Since you know the perimeter, you can plug it in.(you could have also plugged it in in the beginning)
P = 4x + 9
14 = 4x + 9 Subtract 9 on both sides
5 = 4x Divide 4 on both sides
5/4 = x
Now that you know x, find the side length of the square.
(x + 2 1/4)
(5/4 + 2 1/4)
2 6/4 = 3 2/4 = 3 1/2 units or 3.5 units
To find the area of a square, you multiply 2 of the sides together:
A = s · s
A = 3.5 · 3.5
A = 12.25 units²
