Standard form of a circle" (x-h)²+(y-k)²=r², (h,k) being the center, r being the radius.
in this case, h=-2, k=6, (x+2)²+(y-6)²=r²
use the point (-2,10) to find r: (-2+2)²+(10-6)²=r², r=4
so the equation of the circle is: (x+2)²+(y-6)²=4²
Answer:
13(4x-13)
if you distribute it then you come back with 52x-169.
Answer:
x=17
Step-by-step explanation:
Answer:
Step-by-step explanation:
5x=y+6 --------- equ 1
2x-3y=4 -------- equ 2
5x - 6 = y
y = 5x - 6
substitute in equ 2
2x-3(5x - 6) =4
2x - 3*5x + 3*6 = 4
2x - 15x + 18 = 4
- 13x = 4 - 18
-13x = -14
x = -14/-13
x = 14/13
substitute in equ 1
5*14/13 = y+6
70/13 - 6 = y
y = ( 70 - 78)/13
y = -8/13