Answer:
a(n) = 12 * (13)^(n-1)
Step-by-step explanation:
First step is to determine what's the scale/multiplication factor between each term:
156 / 12 = 13
2028 / 156 = 13
So, since we got 13 between 1st, 2nd and 3rd term, we can be confident it's the right multiplication factor.
an would be the first term (12) multiplied by a factor of 13. So,
If we try for n > 1, we have
a(2) = 12 * (13)^(2-1) = 12 * 13 = 156
a(3) = 12 * (13)^(3-1) = 12 * 13² = 12 * 169 = 2028
It matches!
(n^4 - 1) = (n^2 - 1) (n^2 +1) = (n - 1) (n + 1) (n^2 + 1)
Answer:
sugar
Step-by-step explanation:
Answer:
Please check the explanation.
Step-by-step explanation:
Given
f(x) = 3x + x³
Taking differentiate
solving
now solving
Thus, the expression becomes
Thus,
f'(x) = 3 + 3x²
Given that f'(x) = 15
substituting the value f'(x) = 15 in f'(x) = 3 + 3x²
f'(x) = 3 + 3x²
15 = 3 + 3x²
switch sides
3 + 3x² = 15
3x² = 15-3
3x² = 12
Divide both sides by 3
x² = 4
Thus, the value of x will be: