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2 years ago

What is the length of leg s of the triangle below?

Mathematics

2 answers:

kifflom [539]2 years ago

6 0

Answer:

i normally know these but i honestly dont know but can you please put branliest

Step-by-step explanation:

timurjin [86]2 years ago

5 0

Step-by-step explanation:

Keep in mind that this triangle is a 45-45-90 triangle meaning that it's isosceles

This means that the other side is also equal to s

The best way to solve this is by using the pythagorean theorem

$a^{2}$ + $b^{2}$ = $c^{2}$

10 $\sqrt{2}$ = c (because it's the hypotenuse or the longest side)

s = a

s= b

Substitute the values into the formula stated above

$a^{2}$ + $b^{2}$ = $c^{2}$

$s^{2}$ + $s^{2}$ =(10 $\sqrt{2}$ $)^{2}$

Simplify

$2s^{2}$ = $(\sqrt{102} )^{2}$

$2s^{2}$ = 102

Now continue simplifying till you completely solve it

$\frac{2s^{2} }{2}$ = $\frac{102}{2}$

$s^{2}$ = 51

$\sqrt{s^{2} }$ = $\sqrt{51}$

s= $\sqrt{51}$

I hope this helps!!!

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Suppose you have 18 more quarters than dimes. You have a total of $8.00. How many of each coin do you have? Use the substitution

kramer

Answer:

18 quarters = $4.50

8.00-4.50=3.50

10 dimes+10 quarters=$3.50

Answer= you have 10 dimes and 28 quarters

Step-by-step explanation:

7 0

1 year ago

Read 2 more answers

If sin 0=3/5, then cos 0=

vaieri [72.5K]

Answer:

$\frac{4}{5}$

Step-by-step explanation:

Given

sinΘ = $\frac{3}{5}$ = $\frac{opposite}{hypotenuse}$

Then the hypotenuse = 5 and one leg of the right triangle is 3

Using Pythagoras' identity to find the second leg (x)

x² + 3² = 5²

x² + 9 = 25 ( subtract 9 from both sides )

x² = 16 ⇒ x = 4

cosΘ = $\frac{adjacent}{hypotenuse}$ = $\frac{4}{5}$

7 0

2 years ago

What is the z-score of a newborn who weighs 4,000 g?.

vagabundo [1.1K]

The z-score of the considered newborn having 4,000 g weight is $\dfrac{4000 - \mu}{\sigma}$

<h3>How to get the z scores?</h3>

If we've got a normal distribution, then we can convert it to standard normal distribution and its values will give us the z score.

If we have

$X \sim N(\mu, \sigma)$

(X is following normal distribution with mean $\mu$ and standard deviation $\sigma$ )

then it can be converted to standard normal distribution as

$Z = \dfrac{X - \mu}{\sigma}, \\\\Z \sim N(0,1)$

(Know the fact that in continuous distribution, probability of a single point is 0, so we can write

$P(Z \leq z) = P(Z < z) )$

Also, know that if we look for Z = z in z tables, the p value we get is

$P(Z \leq z) = \rm p \: value$

For the considered case, the statement in the problem is missing the mean weight of the newborn and standard deviation of the data set of weights of newborn.

Thus, for them, we can consider variables in place of their actual values.

Let we have:

X = weights of newborns for some considered system (in grams)
$\mu$ = mean weight of newborns (in grams)
$\sigma$ = standard deviation of the data set of weights of newborns

Then, the z-score for X = 4000 is

$z = \dfrac{x - \mu}{\sigma} = \dfrac{4000 - \mu}{\sigma}$

Thus, the z-score of the considered newborn having 4,000 g weight is $\dfrac{4000 - \mu}{\sigma}$

Learn more about z-scores here:

brainly.com/question/13299273

3 0

1 year ago

When the author visited Dublin, Ireland (home of Guinness Brewery employee William Gosset, who first developed the t distributio

disa [49]

Answer:

The Decision Rule

Fail to reject the null hypothesis

The conclusion

There is no sufficient evidence to support the claim that the mean age of the cars is greater than that of taxi

Step-by-step explanation:

From the question we are told that

The data is

Car Ages 4 0 8 11 14 3 4 4 3 5 8 3 3 7 4 6 6 1 8 2 15 11 4 1 6 1 8

Taxi Ages 8 8 0 3 8 4 3 3 6 11 7 7 6 9 5 10 8 4 3 4

The level of significance $\alpha = 0.05$

Generally the null hypothesis is $H_o : \mu_1 - \mu_2 = 0$

the alternative hypothesis is $H_a : \mu_1 - \mu_2 > 0$

Generally the sample mean for the age of cars is mathematically represented as

$\= x_1 = \frac{\sum x_i }{n}$

=> $\= x_1 = \frac{4+ 0+ 8 +11 + \cdots + 8
}{27}$

=> $\= x_1 = 5.56$

Generally the standard deviation of age of cars

$\sigma _1 = \sqrt{\frac{\sum (x_i - \= x)^2}{n_1} }$

=> $\sigma _1 = \sqrt{\frac{(4 - 5.56)^2 + (0 - 5.56)^2+ (8 - 5.56)^2 + \cdots + 8}{ 27} }$

=> $\sigma _1 = 3.88$

Generally the sample mean for the age of taxi is mathematically represented as

$\= x_2 = \frac{\sum x_i }{n}$

=> $\= x_2 = \frac{8 +8 +0 + \cdots + 4
}{20}$

=> $\= x_2 = 5.85$

Generally the standard deviation of age of taxi

$\sigma _2 = \sqrt{\frac{\sum (x_i - \= x)^2}{n_1} }$

=> $\sigma _2 = \sqrt{\frac{(8 - 5.85)^2 + (8 - 5.85)^2+ (0 - 5.85)^2 + \cdots + 8}{ 20} }$

=> $\sigma _2 = 2.83$

Generally the test statistics is mathematically represented as

$t = \frac{(\= x_ 1 - \= x_2 ) - 0}{\sqrt{\frac{\sigma^2_1}{n_1} + \frac{\sigma^2_2}{n_2} } }$

=> $t = \frac{(5.56 - 5.85 ) - 0}{\sqrt{\frac{(3.88)^2}{27} + \frac{(2.83)}{20} }}$

=> $t = -0.30$

Generally the degree of freedom is mathematically represented as

$df = n_1 + n_2 -2$

$df = 27 + 20 -2$

$df = 45$

From the t distribution table the $P(t > t )$ at the obtained degree of freedom = 45 is

$P(t > -0.30 ) = 0.61722067$

So the p-value is

$p-value = P(t > T) = 0.61722067$

From the obtained values we see that the p-value > $\alpha$ hence we fail to reject the null hypothesis

Hence the there is no sufficient evidence to support the claim that the mean age of the cars is greater than that of taxi

5 0

2 years ago

Plzzzzzzz help ill give brainliest and there is no answer choice

Iteru [2.4K]

Step-by-step explanation:

Q.4,1

R.3,2

S 1,0

T.-2. 2

(they may be in the wrong way)

Hope this helps

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2 years ago

Read 2 more answers