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2 years ago

Which set of side lengths can form a triangle?

Mathematics

1 answer:

emmainna [20.7K]2 years ago

4 0

Answer:

C:4 cm, 8 cm, 5 cm

Step-by-step explanation:

sum of length of any two sides of a triangle will be larger than the third side.

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I really need help plzzzzz

Sonbull [250]

ANSWER

D. rotation, translation, reflection

EXPLANATION

Dilation is not a rigid motion.

When the triangle is dilated the image triangle may become bigger ( magnification) or smaller (reduction).

When the scale factor is negative 1, a congruent triangle is obtained.

Hence dilation will not always produce a congruent triangle.

Rotation, reflection and translation are rigid motions and hence will always produce a congruent triangle.

8 0

2 years ago

Find a polynomial function of least degree having only real coefficients, a leading coefficient of 1, and roots of 2-√6 , 2+ √6

horsena [70]

Answer:

$x^{4} -18x^{3}+104x^{2} -172x-100$

Step-by-step explanation:

The 3 roots are given out of which 2 are real and 1 is imaginary. For a polynomial of least degree having real coefficients, it must have a complex conjugate root as the 4th root. Therefore, based on 4 roots, the least degree of polynomial will be 4. Finding the polynomial having leading coefficient=1 and solving it based on multiplication of 2 quadratic polynomials, we get:

$\\\\x_{1} = 2-\sqrt{6} \\x_{2} = 2+\sqrt{6} \\x_{3}=7-i \\x_{4}=7+i \\\\P(x)=1(x-x_{1})(x-x_{2} )(x-x_{3} )(x-x_{4} ) \\\\=(x-(2-\sqrt{6}))( x-(2+\sqrt{6} )) (x-(7-i))( x-(7+i))\\=((x-2)+\sqrt{6})( ( x-2)-\sqrt{6} ) ((x-7)+i)( (x-7)-i)\\=((x-2)^{2} -(\sqrt{6} )^{2} )((x-7)^{2}-(i)^{2})\\=(x^{2} -4x-2)(x^{2} -14x+50)\\=x^{4} -18x^{3}+104x^{2} -172x-100\\$

7 0

2 years ago

pamela wants to buy a new mercedes.The mercedes wheel has a radius of 35', what is the area of the mercedes wheel?

Leokris [45]

Pamela wants to buy a new mercedes.The mercedes wheel has a radius of 35', what is the area of the mercedes wheel? the answer would be 3848.45

5 0

2 years ago

Three consecutive even numbers have a sum where one half of that sum is between 90 and 105.

dexar [7]

$n;\ n+2;\ n+4-three\ consecutive\ even\ numbers\\\\90 \ \textless \ \dfrac{1}{2}(n+n+2+n+4) \ \textless \ 105\\\\90 \ \textless \ \dfrac{1}{2}(3n+6) \ \textless \ 105\ \ \ |multiply\ both\ sides\ by\ 2\\\\180 \ \textless \ 3n+6 \ \textless \ 210\ \ \ |subtract\ 6\ from\ both\ sides\\\\174 \ \textless \ 3n \ \textless \ 204\ \ \ |divide\ both\ sides\ by\ 3\\\\58 \ \textless \ n \ \textless \ 68\\\\Answer:\\60;\ 62;\ 64\ or\ 62;\ 64;\ 66;\ or\ 64;\ 66;\ 68\ or\ 66;\ 68;\ 70.$

5 0

2 years ago

Read 2 more answers

Write the following in simplified radical form.

REY [17]

Step-by-step explanation:

I think the answer is like this

7 0

2 years ago