Here you have a system of 2 equations and 2 unknowns. An easy way to solve this type is to isolate one of the variables.
12a + 2b = 8
2b = 8 - 12a
b =
b = 4 - 6a
Now plug 4 - 6a into equation 1 to solve for a.
a + 5(4 - 6a) = 19
a + 20 - 30a = 19
-29a = -1
a = 1/29 (answer)
Now plug a into the equation for b
b= 4 - 6(1/29)
b= 110/29 (answer)
ANSWER
All real numbers greater or equal to -3.
EXPLANATION
The domain of the given function are values of x that make the function defined.
We can see from the graph that, the domain are x-values greater than or equal to -3.
In other words, we can find a corresponding y-value for all x-values greater than or equal to -3.
The correct answer is option D.
The formula is a permutation in which n represents the sample points in the set, while r represents the number of sample points in each permutation.
Given:
x lies in the III quadrant.
To find:
The values of .
Solution:
It is given that x lies in the III quadrant. It means only tan and cot are positive and others are negative.
We know that,
x lies in the III quadrant. So,
Now,
And,
We know that,
Therefore, the required values are .