This is a matter of plugging in. Specifically 7 for L.
T = 2πsqrt(7/32)
T = (6.28319...)(0.46771...)
T is about 2.93871 seconds
Answer:
See explanation.
Step-by-step explanation:
2) Your written answer is correct, y = x +4
3) Slope of perpendicular line: 5/2
y=mx+b
4 = (5/2)(4) + b
4 = 10 + b
b = -6
So, y=(5/2)x - 6
4) Slope of perpendicular line: 1
y=mx+b
5 = (1)(4) + b
5 = 4 + b
b = 1
So, y = x + 1
7) Slope of perpendicular line: 3/4
y=mx+b
4 = (3/4)(4) + b
4 = 3 + b
b = 1
So, y = (3/4)x + 1
8) Slope of perpendicular line: 1/4
y=mx+b
-2 = (1/4)(0) + b
b = -2
So, y = (1/4)x - 2
Step-by-step explanation:
I'll do the first problem as an example.
∠P and ∠H both have one mark. That means they're congruent.
∠T and ∠G both have two marks. So they're congruent.
∠W and ∠D both have three marks. So they're congruent.
So we can write a congruence statement:
ΔPTW ≅ ΔHGD
We can write more congruence statements by rearranging the letter, provided that corresponding pairs have the same position (P is in the same place as H, etc.). For example:
ΔWPT ≅ ΔDHG
ΔTWP ≅ ΔGDH
Velocity = distance/time
v = d/t = 1/0.5 = 2m/s
My answer is 13+16+19 because we’re are adding 3 each time