Answer:
a) 47.55
b) 58
c) 47.88
Step-by-step explanation:
Given that the size of the orders is uniformly distributed over the interval
$25 ( a ) to $80 ( b )
<u>a) Determine the value for the first order size generated based on 0.41</u>
parameter for normal distribution is given as ; a = 25, b = 80
size/value of order = a + random number ( b - a )
= 25 + 0.41 ( 80 - 25 )
= 47.55
<u>b) Value of the last order generated based on random number (0.6)</u>
= a + random number ( b - a )
= 25 + 0.6 ( 80 - 25 )
= 25 + 33 = 58
<u>c) Average order size </u>
= ∑ order 1 + order 2 + ----- + order 10 ) / 10
= (47.55 + ...... + 58 ) / 10
= 478.8 / 10 = 47.88
Answer:
yes.
Step-by-step explanation:
write these ratios as fractions to see if they are proportional
3/4
9/12 -------> this can be simplified by dividing by 3
= 3/4
therefore yes they are equivalent
Let the full marks be represented by = x
As given, 80% of x is 75
So,
x=
x=93.75
Hence, full marks is 93.75
We can check also- =75
Should be 1,188 , because 1,188 divided by six would be 198, hope I could help