A 10 kg weight is suspended in the air by a strong cable. How much work is done, per unit time, in suspending the weight
1 answer:
Answer:
There is no work done.
Explanation:
<u>Given the following data;</u>
Mass = 10 kg
To find the work done?
In Physics, work done can be defined as the amount of energy transfered when an object or body is moved over a distance due to the action of an external force.
Mathematically, work done is given by the formula;
Work done = force * distance
Where,
- W is the work done
- F represents the force acting on a body.
- d represents the distance covered by the body.
<em>However, the weight suspended in the air by a strong cable does not move or experience any form of displacement. Therefore, there is no work done. </em>
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Answer:
Explanation:
When the central shaft rotates , the seat along with passenger also rotates . Their rotation requires a centripetal force of mw²R where m is mass of the passenger and w is the angular velocity and R is radius of the circle in which the passenger rotates.
This force is provided by a component of T , the tension in the rope from which the passenger hangs . If θ be the angle the rope makes with horizontal ,
T cos θ will provide the centripetal force . So
Tcosθ = mw²R
Tsinθ component will balance the weight .
Tsinθ = mg
Dividing the two equation
Tanθ =
Hence for a given w , θ depends upon g or weight .