Answer:
Fr
Explanation:
Francium (Fr) has the lowest ionization energy, with a value of 4.0727eV. This ionization energy increases as one advances in a period, being greater in the group of nonmetals.
Answer:
6.78 × 10⁻³ L
Explanation:
Step 1: Write the balanced equation
Mg₃N₂(s) + 3 H₂O(g) ⇒ 3 MgO(s) + 2 NH₃(g)
Step 2: Calculate the moles corresponding to 10.2 mL (0.0102 L) of H₂O(g)
At STP, 1 mole of H₂O(g) has a volume of 22.4 L.
0.0102 L × 1 mol/22.4 L = 4.55 × 10⁻⁴ mol
Step 3: Calculate the moles of NH₃(g) formed from 4.55 × 10⁻⁴ moles of H₂O(g)
The molar ratio of H₂O to NH₃ is 3:2. The moles of NH₃ produced are 2/3 × 4.55 × 10⁻⁴ mol = 3.03 × 10⁻⁴ mol.
Step 4: Calculate the volume corresponding to 3.03 × 10⁻⁴ moles of NH₃
At STP, 1 mole of NH₃(g) has a volume of 22.4 L.
3.03 × 10⁻⁴ mol × 22.4 L/mol = 6.78 × 10⁻³ L
<h3><u>Answer;</u></h3>
Molar mass
<h3><u>Explanation</u>;</h3>
- Stoichiometry involves the study of quantitative relationships between the amounts of reactants used and products formed by a chemical reaction.
- A conversion factor is a ratio of coefficients found in a balanced reaction, which can be used to inter-convert the amount of products and reactants.
- Molar ratios, or conversion factors, identify the number of moles of each reactant needed to form a certain number of moles of each product.
answer: the variable part of an amino acid is the: SIDE CHAIN
Answer:
Substrate:alkyl halide
Leaving group: Cl
Organic product: The nitrile
Inorganic product: Cl-
Nucleophile: CN-
Explanation:
An SN2 reaction is a concerted bimolecular reaction. Concerted means that it involves two reactions taking place at the same time while bimolecular means that the rate determining step involves two molecules. The cyanide ion attacks the alkyl halide from the rear. In the transition state, the leaving group (Cl-) is departing while the nucleophile (CN-) is forming a bond to the alkyl halide simultaneously. The alkyl halide is the substrate in the reaction. The organic product is the nitrile shown in the image attached.