If a 4N weight is hung on a spring, and it extends by 0.2m, what is the spring constant (k)?

Physics

2 answers:

tresset_1 [31]2 years ago

6 0

Answer:

20 N/m

Explanation:

4/0.2 = 20 N/m

/ = divide

Naddika [18.5K]2 years ago

4 0

Answer: 200 N/m

Explanation:

The Gravitational spring energy(Us) is equal to 1/2kx^2. So we have x as .2 m and Us as 4 N. So 4 N = 1/2 * k * .2^2. So now we solve for K and get 200 N/m.

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