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2 years ago

9

All moving objects have momentum. momentum refers to the momentum of objects moving in a straight line and momentum refers

to the momentum of rotating objects.

1 answer:

Inessa [10]2 years ago

3 0

Answer: linear,angular

Explanation:

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It's for #8....I know the answer is 293.2 ft I just don't know how to get it

Oksi-84 [34.3K]

Kinectic Energy=1/2(mass)(velocity)^2 so 1.2=1/2(.0012)(position/2) so it travels 4000 m. Not sure how it is 293.2 ft

7 0

2 years ago

A body is accelerated continuously. What is the form of the graph?

Inga [223]

That depends on what quantity is graphed.

It also depends on what kind of acceleration is taking place ...
continuous change of speed or continuous change of direction.

-- If the graph shows speed vs time, and the acceleration is a change
in speed, then the graph is a connected series of straight-line pieces.
Each straight piece slopes up if speed is increasing, or down if speed
is decreasing.

-- If the graph shows speed vs time, and the acceleration is a change in
direction only, then the graph is a straight horizontal line, since speed is
constant.

-- If the graph shows direction vs time, and the acceleration is a change
in speed only, then the graph is a straight horizontal line, since direction
is constant.

-- If the graph shows direction vs time, and the acceleration is a change
in direction, then the graph is a connected series of pieces of line.
Each piece may be straight if the direction is changing at a constant rate,
or curved if the direction is changing at a rate which grows or shrinks.
Each piece may slope up if the angle that defines the direction is growing,
or may slope down if the angle that defines the direction is decreasing.

-- If the graph shows distance vs time, and the acceleration is a
change in speed, then the graph is a connected series of pieces
of curves. Each piece curves up if speed is increasing, or down if
speed is decreasing.

-- If the graph shows distance vs time, and the acceleration is a change
in direction only, then the graph is a straight line sloping up, since speed
is constant.

6 0

2 years ago

How is the combined gas law used to calculate changes in pressure, temperatures, and/or volume for a fixed amount of gas?

nalin [4]

Answer:

Let's start by considering the ideal gas law:

$pV=nRT$

where

p is the gas pressure

V is its volume

n is the number of moles

R is the gas constant

T is the absolute temperature

This equation can also be rewritten as

$\frac{pV}{T}=nR$

Now, if we consider a fixed amount of gas, this means that the number of moles (n) is constant. So we can rewrite the equation as

$\frac{pV}{T}=const.$

And therefore, if we consider a gas undergoing a certain transformation from 1 to 2, we can write

$\frac{p_1V_1}{T_1}=\frac{p_2V_2}{T_2}$

where 1 indicates the conditions of the gas at the beginning and 2 the conditions of the gas after the process. So, the change in pressure/temperature/volume of the gas can be found by using this equation.

5 0

2 years ago

A child is perched perilously above a 150m ravine. The child has a mass of 45kg. How much

Finger [1]

Answer:

<em>U = 66,150 J</em>

Explanation:

<u>Gravitational Potential Energy</u>

Gravitational potential energy is the energy stored in an object because of its vertical position or height in a gravitational field.

It can be calculated with the equation:

U=m.g.h

Where m is the mass of the object, h is the height with respect to a fixed reference, and g is the acceleration of gravity or $9.8\ m/s^2$ .

The child of mass m=45 Kg is perched above a h=150 m ravine. His gravitational potential energy is:

$U=45~Kg\cdot 9.8\ m/s^2\cdot 150\ m$

U = 66,150 J

6 0

2 years ago

What frequency is received by the ambulance after reflecting from a wall near the person watching the oncoming ambulance (as in

Zepler [3.9K]

Answer:

900.48925 Hz

979.9785 Hz

Explanation:

$v_a$ = Relative velocity of ambulance = $109\ km/h=\dfrac{109}{3.6}$

$v_w$ = Velocity of wall = 0

v = Velocity of sound in air = 343 m/s

From doppler effect we have

$f=f'\dfrac{v+v_w}{v-v_a}\\\Rightarrow f=821\dfrac{343+0}{343-\dfrac{109}{3.6}}\\\Rightarrow f=900.48925\ Hz$

The frequency of sound is 900.48925 Hz

When the wall acts like a source

$f=f'\dfrac{v+v_a}{v-v_w}\\\Rightarrow f=900.48925\dfrac{343+\dfrac{109}{3.6}}{343-0}\\\Rightarrow f=979.9785\ Hz$

The frequency of sound is 979.9785 Hz

4 0

2 years ago