1. A set of weights includes a 5 lb barbell and 8 pairs of weight plates. Each pair, p,

Mathematics

1 answer:

lidiya [134]2 years ago

6 0

Answer:

5 <= y <= 85

Step-by-step explanation:

Since the lowest weight possible is 5lbs (just the barbell and no weights) the lowest point of the range is 5lbs (the y intercept when x = 0)

The highest weight possible is 85lbs since, there is only 8 pairs of weight plates (8 is the input value) and the pairs each weigh 10lbs (the slope of the graph) + 5lbs from the barbell (y-intercept).

Using the function given, if you input 8 as the x value, you get

85 = 10(8) + 5

So the highest value of the range is 85lbs, therefore the range is 5 <= y <= 85.

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You have 8 times as many dimes as nickels. You have 18 dimes

fenix001 [56]

Answer:

$1.70

Step-by-step explanation:

Let the number of nickels be $x$ .

Thus, by the problem statement, the number of dimes is [/tex] 8 \cdot x = 8x. [/tex]

Therefore, there are $8x + x = 9$ coins in total. To find what $x$ is, we need to solve the equation $9x = 18.$ This can be done by dividing both sides by $9$ which gives $x=2$ . Plugging these values in tells us that there are $2$ nickels and $16$ dimes. (Test it out!) Thus, the nickels are worth $2 \cdot 5 = 10$ cents and the dimes are worth $16 \cdot 10 = 160$ cents, so in all, you have $10 + 160 = 170$ cents which is $1.70.