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2 years ago

Write an algebraic expression to represent- "nine fewer than a number, n, squared"

Mathematics

1 answer:

Ganezh [65]2 years ago

7 0

Answer:

$(n-9)^{2}$

Step-by-step explanation:

Nine fewer than N, squared. If it's wrong, tell me and clarify more explicitly. I'll fix it if so.

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THIS IS VERY SIMPLE BUT I GET CONFUSED SOMETIMES LOL

Bogdan [553]

Answer:

the answer is 24

Step-by-step explanation:

15-(-9)=24

7 0

2 years ago

Read 2 more answers

Please helpp!!!!

fomenos

Answer:

Dom(gof)=Dom(f)={1,3,4}.

(gof)(1)=g{f(1)}=g(2)=3.

(gof)(3)=g{f(3)}=g(5)=1.

(gof)(4)=g{f(4)}=g(1)=3.

∴gof={(1,3),(3,1),(4,3)}.

7 0

2 years ago

Its super duper easy but im having some trouble<br> so can someone help me?

Klio2033 [76]

together = add

add the fractions

3 7/10 + 5 9/10

add the whole numbers first

3+5=8

add the fractions

7/10+9/10= 16/10

8 16/10

reduce 16/10 divide by 2

16/2= 8

10/2= 5

8 8/5

whole number changes to 9

8-5=3

denominator stays the same

9 3/5

Answer:

9 3/5

8 0

2 years ago

IRISSAK [1]

Your answer is A 1/15

6 0

3 years ago

Read 2 more answers

Given the position of the particle, what the position(s) of the particle when it’s at rest

choli [55]

The position function of a particle is given by:

$X\mleft(t\mright)=\frac{2}{3}t^3-\frac{9}{2}t^2-18t$

The velocity function is the derivative of the position:

$\begin{gathered} V(t)=\frac{2}{3}(3t^2)-\frac{9}{2}(2t)-18 \\ \text{Simplifying:} \\ V(t)=2t^2-9t-18 \end{gathered}$

The particle will be at rest when the velocity is 0, thus we solve the equation:

$2t^2-9t-18=0$

The coefficients of this equation are: a = 2, b = -9, c = -18

Solve by using the formula:

$t=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}$

Substituting:

$\begin{gathered} t=\frac{9\pm\sqrt[]{81-4(2)(-18)}}{2(2)} \\ t=\frac{9\pm\sqrt[]{81+144}}{4} \\ t=\frac{9\pm\sqrt[]{225}}{4} \\ t=\frac{9\pm15}{4} \end{gathered}$

We have two possible answers:

$\begin{gathered} t=\frac{9+15}{4}=6 \\ t=\frac{9-15}{4}=-\frac{3}{2} \end{gathered}$

We only accept the positive answer because the time cannot be negative.

Now calculate the position for t = 6:

$undefined$

6 0

10 months ago