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2 years ago

If the electronnegavity difference between elements A and X is 0.8, the bond in AX will most likely be what?

Chemistry

1 answer:

siniylev [52]2 years ago

8 0

Answer:

Polar covalent bond

Explanation:

When the electronegativity difference between two elements A and X is 0.8, the bond AX formed will most likely be a polar covalent bond.

A polar covalent bond is one whose electronegativity difference is between 0.5 and 2.1.

In such a bond type, we have heteronuclear species with one of the species having a higher electronegativity value.

When electronegativity difference is less than 0.5, a non-polar covalent bond forms.
If the value is greater than 2.1, an ionic bond will form.

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The periodic table has mass units for every element that can be correlated with the number of atoms of that element. The relationship is known as Avogadro's Number. This number, 6.02x $10^{23}$ , is nicknamed the mole, which scientists found to be a lot more catchy, and easier to write than 6.02x $10^{23}$ . The mole is correlated to the atomic mass of that element. The atomic mass of sulfur, S, is 36.02 AMU, atomic mass units. But it can also be read as 36.02 grams/mole.

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