Yo sup??
The given points are (1,1),(1,3) and (9,2)
equation of circle is
8x²+8y²+ax+by=0
let us plug in (1,1) in the equation we get
8+8+a+b=0
a+b=-16
let us now plug in (1,3) in the equation
8+8*3²+a+3b=0
a+3b=-80
let us. now solve the two equation in terms of a and b
we get
2b=--64
b=-32
and
a=-16+32
=16
therefore the equation is
8x²+8y²+16x-32y=0
Hope this helps
Second one is correct, that is an identity.
Third one is a contradiction:
6x - 15 = 3 * (2x - 6) ------> 6x - 15 = 6x - 18
Fourth one:
5x - 3 * (x - 4) = 2 * (x - 6) ---> 5x - 3x + 12 = 2x - 12 ---> 2x + 12 = 2x -12
So this is a contradiction as well.
At least we're both struggling with the same type of math ; -;
The value of x is 27
Explanation:
5x-50=3x+4
5x-3x=4+50
2x=54
x=27
