the whole triangle is call an acute equilibrium triangle if that's the answer your looking for if not I need to see the whole question
Answer:
Step-by-step explanation:
we know that
The measurement of the external angle is the semi-difference of the arcs which comprises
In this problem
m∠RPS= ------> external angle
so
m∠RPS=
we have
m∠RPS=
substitute the values
Solve for arc RS
Tan²( θ ) - (1 + √3) tan (θ) + √3 = 0
tan²( θ ) - (tan (θ) + √3 tan (θ)) + √3 = 0
tan²( θ ) - tan (θ) - √3 tan (θ) + √3 = 0
tan( θ ) ( tan (θ) - 1) - √3 ( tan (θ) - 1 ) = 0
( tan( θ ) - 1 ) ( tan( θ ) - √3 ) = 0
tan( θ ) - 1 = 0
θ = π/₄
tan( θ ) - √3 = 0
θ = π/₃
so θ = π/₄ and θ = π/₃
Answer:
1. yes
2. yes
3. no
4. no
Step-by-step explanation:
Replace x by each value of x.
1. yes
2. yes
3. no
4. no (this is not a solution because the value must be greater than 44 not equal to)
What are u actually doing