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2 years ago

Given f(x) = 3x-1 and g(x) = 2x-3 for which value of x does g(x) = f2)?

Mathematics

1 answer:

Zarrin [17]2 years ago

7 0

Answer:

Step-by-step explanation:

f(x) = 3x - 1, plug in 2 for x in f(x)

3 x (2) - 1 --> 6 - 1 --> 5, plug in 5 for x in g(x)

2 x (5) - 3 --> 10 - 3 --> 7

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Find the mean, variance, and standard deviation of the binomial distribution with the given values of n and p. , The mean, ,

klemol [59]

Complete Question

Find the mean, variance, and standard deviation of the binomial distribution with the given values of n and p. , The mean, , is nothing. (Round to the nearest tenth as needed.)

p = 0.6 n = 18

Answer:

The mean $\mu = 10.5$

The standard deviation $\sigma = 2.08$

The variance $var = 4.32$

Step-by-step explanation:

From the question we are told that

The probability of success is $p = 0.6$

The sample size is $n = 18$

Generally given that the distribution is binomial, then the probability of failure is mathematically represented as

$q = 1- p$

substituting values

$q = 1- 0.6$

$q =0.4$

Generally the mean is mathematically evaluated as

$\mu = np$

substituting values

$\mu = 18 * 0.6$

$\mu = 10.5$

The standard deviation is evaluated as

$\sigma = \sqrt{npq}$

substituting values

$\sigma = \sqrt{18 * 0.6 * 0.4}$

$\sigma = 2.08$

The variance is evaluated as

$var = \sigma^2$

substituting value

$var = 2.08^2$

$var = 4.32$

4 0

3 years ago

Name the segments in the figure below..

VladimirAG [237]

The answer is line becuase a line is the only segment out fo the three types with arrows on eather end

hope this helps

<------> line
0----------0 segment
0------------> ray

5 0

2 years ago

X plus 1/3 equals nine enter your answer in the box in simplest form

LekaFEV [45]

$= > x + \frac{1}{3} = 9$

$\text{Add} \: - \frac{1}{3} \: \text{ on both sides ,}$

$= > x + \frac{1}{3} - \frac{1}{3} = 9 - \frac{1}{3} \\ \\ \\ \\ = > x = \frac{(9 \times 3) - 1}{3} \\ \\ \\ \\ = > x = \frac{27 - 1}{3} \\ \\ \\ \boxed{ \bold{= > x = \frac{26}{3} }} \\ \\ \\ or , \boxed{ \bold{ \: x = 8. \bar{6}}}$

Hence,

$Value \: \: \: of \: \: x \: \: is \: \frac{26}{3} \: \: \: or \: \: \: 8. \bar{6}$