Explanation:
It is given that,
The volume of a right circular cylindrical, 
We know that the volume of the cylinder is given by :
............(1)
The upper area is given by :
For maximum area, differentiate above equation wrt r such that, we get :
r = 1.83 m
Dividing equation (1) with r such that,
Hence, this is the required solution.
Answer:
not work.
Explanation:
if u are saying in a series circuit...
if 1 build burns out and theres other bulbs the circuit wont work anymore.
Given Information:
KEa = 9520 eV
KEb = 7060 eV
Electric potential = Va = -55 V
Electric potential = Vb = +27 V
Required Information:
Charge of the particle = q = ?
Answer:
Charge of the particle = +4.8x10⁻¹⁸ C
Explanation:
From the law of conservation of energy, we have
ΔKE = -qΔV
KEb - KEa = -q(Vb - Va)
-q = KEb - KEa/Vb - Va
-q = 7060 - 9520/27 - (-55)
-q = 7060 - 9520/27 + 55
-q = -2460/82
minus sign cancels out
q = 2460/82
Convert eV into Joules by multiplying it with 1.60x10⁻¹⁹
q = 2460(1.60x10⁻¹⁹)/82
q = +4.8x10⁻¹⁸ C
Answer:
66.26 m/s
Explanation:
Horizontal velocity, Vx = 55.3 m/s
Vertical velocity, Vy = 36.5 m/s
The value of the resultant velocity is given by the vector sum of the two velocities which are acting at 90°.
V = 66.26 m/s
Thus, the velocity of the vehicle is 66.26 m/s along its descent path.
