5-2/2
Divide first due to division coming before addition in pemdas
5-1
4
perimeter should be 43 and the area should be 72m^2
this is squared btw
Answer: 12 students
Step-by-step explanation:
Let X and Y stand for the number of students in each respective class.
We know:
X/Y = 2/5, and
Y = X+24
We want to find the number of students, x, that when transferred from Y to X, will make the classes equal in size. We can express this as:
(Y-x)/(X+x) = 1
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We can rearrange X/Y = 2/5 to:
X = 2Y/5
The use this value of X in the second equation:
Y = X+24
Y =2Y/5+24
5Y = 2Y + 120
3Y = 120
Y = 40
Since Y = X+24
40 = X + 24
X = 16
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Now we want x, the number of students transferring from Class Y to Class X, to be a value such that X = Y:
(Y-x)=(X+x)
(40-x)=(16+x)
24 = 2x
x = 12
12 students must transfer to the more difficult, very early morning, class.
We write to expressions since there are two unknown here which is x and y. The first expression is the <span>sum of two numbers, x and y, is 12.
x + y = 12
The second expression is that the </span><span>difference of x and two times y is 6.
x -2y = 6
Therefore, the values of x and y are 10 and 2.</span>
Answer: -300 meters
Step-by-step explanation: If he started from 0 (sea level) and went 300 meters under, meaning 0-300=-300 meters.