Mean number of errors in each page = 0.01
Mean number of errors in 100 pages = 0.01*100=1
It is possible to use the cumulative distribution function (CMF), but the math is a little more complex, involving the gamma-function. Tables and software are available for that purpose.
Thus it is easier to evaluate with a calculator for the individual cases of k=0,1,2 and 3.
The Poisson distribution has a PMF (probability mass function)
with λ = 1
=>
=>
or
P(k<=3)=
0.9810 (to four decimal places)
common difference, d = -3
f1 = -13
An arithmetic sequence f(n) = f1 + d(n - 1)
so f(n) = -13 - 3(n - 1)
f(46) = -13 - 3(46-1) = -13 -3(45) = -13 - 135 = -148
Answer:
f(46) = - 148
Answer:
its teaspoons
Step-by-step explanation:
Answer:
m+5nx(9-p)-6-2r
Step-by-step explanation:
here you go
Answer:
Answer: B
Step-by-step explanation:
just solve keep up learning!