The exponential function that passes through (0,2) and (3,54) is a growth function
The exponetial function is y = 2 * 3^x
<h3>How to construct the exponential function?</h3>
The points are given as:
(x,y) = (0,2) and (3,54)
An exponential function is represented as:
y = ab^x
Substitute the points in the equation
2 = ab^0 and 54 = ab^3
Solve 2 = ab^0
a = 2
Substitute 2 for a in 54 = ab^3
54 = 2b^3
Divide by 2
27 = b^3
Take the cube roots of both sides
b = 3
So, we have:
y = ab^x
This becomes
y = 2 * 3^x
Hence, the exponetial function is y = 2 * 3^x
Read more about exponential functions at:
brainly.com/question/24077767
Let's compare apples to apples and oranges to oranges: convert each given proper fraction into its decimal counterpart:
3 63/80 => 3 .788 approx.
3 1/5 => 3.2
3 11/20 => 3.55
It's now an easy matter to arrange these numbers from least to greatest:
3.2, 3.55, 3.79, or
3 1/5, 3 11/20, 3 63/80
He puts 15 markers in the box. Hope this helps.
9514 1404 393
Answer:
cos(x) = 0.6
Step-by-step explanation:
First, we need to find UQ.
UQ = UP·cos(y°) = UP·√(1 -sin²(y°)) = (26 cm)√(1 -25/169) = (26 cm)(12/13)
UQ = 24 cm
Then TQ is ...
TQ = 1/3UQ = 1/3(24 cm) = 8 cm
And cos(x°) is ...
cos(x°) = √(1 -sin²(x)) = √(1 -64/100)
cos(x°) = 6/10 = 3/5
cos(x°) = 3/5 = 0.6