For this problem you need to put the x values in for x in the equation. For example, put -10 in for x and calculate y, which is g(x)
Answer:
If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is is dA/dt = 15 - 0.005A
Option C) dA/dt = 15 - 0.005A is the correction Answer
Step-by-step explanation:
Given the data in the question;
If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is?
dA/dt = rate in - rate out
first we determine the rate in and rate out;
rate in = 3pound/gallon × 5gallons/min = 15 pound/min
rate out = A pounds/1000gallons × 5gallons/min = 5Ag/1000pounds/min
= 0.005A pounds/min
so we substitute
dA/dt = rate in - rate out
dA/dt = 15 - 0.005A
Therefore, If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is is dA/dt = 15 - 0.005A
Option C) dA/dt = 15 - 0.005A is the correction Answer
<h2>
Answer: (3/2)x - 2</h2>
Step-by-step explanation:
Let the number be x.
"Two less than 3/2 of a number (x)" means (3/2)x - 2
"is no more than" means "≤"
5 1/2
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I can't see the whole problem
Answer:
337.5 and also 202.5
Step-by-step explanation:
do 8x = 540 since 5 and 3 are in a ratio... so you get 5x plus 3x. Then you solve for x and get 67.5..67.5 times 3 is 202.5 and 67.5 times 5 is 337.5.