now substitute the x for (y+4) in the second equation (y+4)+y=20 2y+4=20 2y=16 y=8 now substitute 8 for y in the first equation x=8+4 x=12 so y=8 and x=12
Answer:It's the last option again. You have 1 linear factor (3x) and 2 copies of a quadratic factor (x² + 10), and the partial fractions with the quadratic factor need to have a linear polynomial in the numerator.