Question

The pair 3x+4y+2=0 and 4x-5y+13=0 of linear equation has​

Answer 1

Answer:

Unique solution

Step-by-step explanation:

Given

$3x+4y+2=0$

$4x-5y+13=0$

Required

The type of solution

A linear equation is represented as:

$Ax + Bx + C =0$

For the first equation:

$A_1 = 3\ B_1 = 4\ C_1 = 2$

For the second:

$A_2 = 4\ B_2 = -5\ C_2 = 13$

We have:

$\frac{A_1}{A_2} = \frac{3}{4}$

$\frac{B_1}{B_2} = -\frac{4}{5}$

By comparison:

$\frac{A_1}{A_2} \ne \frac{B_1}{B_2}$

Hence, the system has a unique solution.