Answer:
9 L
Explanation:
According to the question , the given reaction is -
2NO(g) + O₂(g)------->2NO₂(g)
Since ,
At STP ,
One mole of a gas occupies the volume of 22.4 L.
Hence , as given in the question -
9 L of NO , i.e .
22.4 L = 1 mol
1 L = 1 / 22.4 mol
9 L = 1 / 22.4 * 9 L = 0.40 mol
From the chemical reaction ,
The Oxygen is in excess , hence NO becomes the limiting reagent , and will determine the moles of product .
Hence ,
2 moles of NO will produce 2 moles of NO₂.
Therefore ,
0.40 mol of NO will produce 0.40 mol of NO₂.
Hence , the volume of NO₂ can be calculated as -
1 mol = 22.4 L
0.40 mol = 0.40 * 22.4 L = 9 L
Li2CO3 + 2HNO3 ----> 2LiNO3 + H2O + CO2
1.8 L
<h3>
Explanation</h3>
The volume of a gas, V, is inversely proportional to the pressure on it, P. That is:
V₁ · T₁ = V₂ · T₂.
Rearranging gives:
V₂ = V₁ · T₁ / T₂ = 4.2 × (101 / 235) = 1.8 L
