specific gravity of the unknown sample = 2.68
Explanation:
True weight of solid=31.6 N
Apparent weight=19.8 N
loss in weight= 31.6-19.8=11.8 N
Loss in weight= weight of the liquid displaced
so weight of water displaced= 11.8 N
now specific gravity= weight of object/ weight of liquid displaced
specific gravity= 31.6/11.8
specific gravity= 2.68
Final speed of 50. Meters second acceleration 92
Answer:
Explanation:
Given data
Temperature T1=270K
Temperature T2=650K
Work=4.3 kJ
Heat rejects=8.0 kJ
To find
Thermal efficiency
Solution
The thermal efficiency is given as:
For Carnot cycle efficiency
For real cycle efficiency
So the thermal efficiency is:
Answer:
Explanation:
Not sure what you're trying to solve... I just know that this is the Coulomb's law.
Complete Question
A small object moves along the x-axis with acceleration ax(t) = −(0.0320m/s3)(15.0s−t)−(0.0320m/s3)(15.0s−t). At t = 0 the object is at x = -14.0 m and has velocity v0x = 7.10 m/s. What is the x-coordinate of the object when t = 10.0 s?
Answer:
The position of the object at t = 10s is
Explanation:
From the question we are told that
The acceleration along the x axis is
The position of the object at t = 0 is x = -14.0 m
The velocity at t = 0 s is
Generally from the equation for acceleration along x axis we have that
=>
=>
At t =0 s and
=>
=>
So
=>
=>
At t =0 s and x = -14.0 m
=>
So
At t = 10.0 s
=>