Answer:
0.486 L
Explanation:
Step 1: Write the balanced reaction
2 KCIO₃(s) ⇒ 2 KCI (s) + 3 O₂(g)
Step 2: Calculate the moles corresponding to 1.52 g of KCIO₃
The molar mass of KCIO₃ is 122.55 g/mol.
1.52 g × 1 mol/122.55 g = 0.0124 mol
Step 3: Calculate the moles of O₂ produced from 0.0124 moles of KCIO₃
The molar ratio of KCIO₃ to O₂ is 2:3. The moles of O₂ produced are 3/2 × 0.0124 mol = 0.0186 mol
Step 4: Calculate the volume corresponding to 0.0186 moles of O₂
0.0186 moles of O₂ are at 37 °C (310 K) and 0.974 atm. We can calculate the volume of oxygen using the ideal gas equation.
P × V = n × R × T
V = n × R × T/P
V = 0.0186 mol × (0.0821 atm.L/mol.K) × 310 K/0.974 atm = 0.486 L
Answer:
The similarity is that Elements and Compunds exist in stable form because of the bonds formed between their atoms. The difference is that an element is a material that consists of a single type of atom and a compound consists of two or more types of elements held together by covalent or ionic bonds.
Explanation: Google
Answer:
Cl2, Chlorine molecule has a boiling point closest to that of argon.
This is because Chlorine is made up of discrete and simple molecules making up a simple molecular structure. The molecules associate through weak van der waal's forces of attraction hence low boiling point.
HCl <em>has</em><em> </em><em>strong</em><em> </em><em>hydrogen</em><em> </em><em>bonds</em><em>.</em>
F2 <em>is</em><em> </em><em>very</em><em> </em><em>small</em><em> </em><em>hence</em><em> </em><em>strong</em><em> </em><em>forces</em><em> </em><em>of</em><em> </em><em>attraction</em><em>.</em>
HF <em>has</em><em> </em><em>strong</em><em> </em><em>hydr</em><em>ogen</em><em> bonds</em>
Answer: A. and
Explanation:
Galvanic cell is a device which is used for the conversion of the chemical energy produces in a redox reaction into the electrical energy.
The standard reduction potential for aluminium and gold are as follows:
Reduction takes place easily if the standard reduction potential is higher (positive) and oxidation takes place easily if the standard reduction potential is less (more negative).
Here Al undergoes oxidation by loss of electrons, thus act as anode. Gold undergoes reduction by gain of electrons and thus act as cathode.
Anode :
Cathode :
Thus magnesium gets oxidized.