Evaluate
0
∫ ( 3^3 - 5^2) dx
-2
1 answer:
3^3 = 27
5^2 = 25
27 - 25 = 2
integral of 2 = 2x
(2x) evaluated from -2 to 0
= (0) - (2(-2)) = -(-4) = 4
If you did not make any mistakes in typing your question
the answer would be 4
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Answer is 1/9
Hope it help!!
P(t)=6t
A(p)=πp^2, since p(t)=6t
A(t)=π(p(t))^2
A(t)=π(6t)^2
A(t)=36πt^2, so when t=8 and approximating π≈3.14
A(8)≈36(3.14)(8^2)
A(8)≈36(3.14)64
A(8)≈7234.56 u^2
c is the answer i know this because im smart and because c is the answer
P(H) = 1/2
P(>6) = 9/15 = 3/5
P(Both H AND >6) = 1/2 * 3/5 = 3/10
