2 years ago

What point located in quadrant I has an x-value that is 2 units from the origin and a y-value 7 units from the origin?

Mathematics

2 answers:

timurjin [86]2 years ago

8 0

The answer is point V

vivado [14]2 years ago

7 0

Answer:

I believe that the answer would be the letter X. The Y units always go left and right (right if positive, left if negative) and the X units always go up and down (up if positive, down if negative).

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A polynomial function with rational coefficients has the following zeros. Find all additional zeros.

leonid [27]

1 + 3i, - sqrt 10 would be the other two answers

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2 years ago

IM GIVING 20 POINTS AND BRAINLY TO WHO GETS IT RIGHT THIS IS DUE REALLY SOON AND I NEED HELP PLSSSS

Bezzdna [24]

Answer:

5/6

Step-by-step explanation:

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2 years ago

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Solve. −6 1/4x=−3 1/8 What is the solution to the equation? Enter your answer as a simplified fraction in the box.

tresset_1 [31]

X would be equal to -0.5

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1 year ago

Suppose that prior to conducting a coin-flipping experiment, we suspect that the coin is fair. How many times would we have to f

BabaBlast [244]

Answer:

153 times

Step-by-step explanation:

We have to flip the coin in order to obtain a 95.8% confidence interval of width of at most .14

Width = 0.14

ME = $\frac{width}{2}$

ME = $\frac{0.14}{2}$

ME = $0.07$

$ME\geq z \times \sqrt{\frac{\widecap{p}(1-\widecap{p})}{n}}$

use p = 0.5

z at 95.8% is 1.727(using calculator)

$0.07 \geq 1.727 \times \sqrt{\frac{0.5(1-0.5)}{n}}$

$\frac{0.07}{1.727}\geq sqrt{\frac{0.5(1-0.5)}{n}}$

$(\frac{0.07}{1.727})^2 \geq \frac{0.5(1-0.5)}{n}$

$n \geq \frac{0.5(1-0.5)}{(\frac{0.07}{1.727})^2}$

$n \geq 152.169$

So, Option B is true

Hence we have to flip 153 times the coin in order to obtain a 95.8% confidence interval of width of at most .14 for the probability of flipping a head

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2 years ago

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katovenus [111]

Answer:

I think Quadrant 1. I;m not trying to just answer for the points

Step-by-step explanation:

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2 years ago