Answer:
Step-by-step explanation:
A circle centered at (0,0) with radius r is 
Since your circle has diameter of 12, then its radius is 6. Then 
So a possible answer is:
If you want to move the location of the center, but keep it on the x-axis, then add or subtract a number to the x, such as this:
The center of this circle would be (-4, 0) which is still on the x-axis.
The photos are in the wrong way :(
Step-by-step explanation:
The random numbers are selected randomly. Just because they happen to be 6 numbers in a row does not mean that they were not. If she is confident in the random number generator, which can be assumed, then the random numbers were still randomly selected and can be used. To regenerate would be a mistake because Jada is then picking and choosing which random numbers are chosen, defeating the purpose of a random number generator
First, I would multiply the last two fractions because they're smaller and easier to work with:
Now that we've simplified it, we could multiply these terms and simplify. An easier method, however, would be to cancel out any common factors among the numerators and denominators before multiplying:
We can now multiply these terms:
The <span>product of 8/15, 6/5, and 1/3 is B, 16/75.</span>
