<span>Consider a angle â BAC and the point D on its defector
Assume that DB is perpendicular to AB and DC is perpendicular to AC.
Lets prove DB and DC are congruent (that is point D is equidistant from sides of an angle â BAC
Proof
Consider triangles ΔADB and ΔADC
Both are right angle, â ABD= â ACD=90 degree
They have congruent acute angle â BAD and â CAD( since AD is angle bisector)
They share hypotenuse AD
therefore these right angle are congruent by two angle and sides and, therefore, their sides DB and DC are congruent too, as luing across congruent angles</span>
Answer:
k(4) = 10
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
k(x) = 18 - 2x
k(4) is x = 4
<u>Step 2: Evaluate</u>
- Substitute in <em>x</em>: k(4) = 18 - 2(4)
- Multiply: k(4) = 18 - 8
- Subtract: k(4) = 10
your answer would be that the sematry would be vertical semmetry
you can't factorize it in rational numbers
Answer:
..so easy B
Step-by-step explanation:
its B
u put 2nd one in the formula.
