Let y = 12 e^2x
e^2x = y/12
Taking
[email protected]ln e^2x = ln (y/12)
2x = ln (y/12)
x = (1/2) ln (y / 12)
so the inverse h-1(x) = (1/2) ln ( x / 12)
Use MATH-WAY it has all the answer
4) -0.3 = -1/3 < -1/7 since the bigger a negative number is the less positive it is. 1/8 is positive so it is clear that it should be placed last. & thus do all options this way.
5) B
Area of a triangle = ½ bh.
where b = base &
h = height.
Area of outer shape = (½ x 16 x 12) in^2.
= 96 in^2.
Area of unshaded inner shape = (½ x 3 x 4) in^2.
= 6 in^2.
Area of shaded region = (96 – 6) in^2.
= 90 in^2.
You need to first set up the equation:
It would look like 90 divided by 360 multiplied by the given
circumference which is 72 cm.
So 90 / 360 x 72
Simply the fraction above, it will give us:
¼ x 72
So the answer would be 18 cm that is the length of DE (minor
arc)
Answer:
17>n is the correct answer