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Answer with explanation</u>
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Let be the distance traveled by deluxe tire .
As per given , we have
Null hypothesis :
Alternative hypothesis :
Since is left-tailed and population standard deviation is known, thus we should perform left-tailed z-test.
Test statistic :
where, n= sample size
= sample mean
= Population mean
=sample standard deviation
For , we have
By using z-value table,
P-value for left tailed test : P(z≤-2.23)=1-P(z<2.23) [∵P(Z≤-z)=1-P(Z≤z)]
=1-0.9871=0.0129
Decision : Since p value (0.0129) < significance level (0.05), so we reject the null hypothesis .
[We reject the null hypothesis when p-value is less than the significance level .]
Conclusion : We do not have enough evidence at 0.05 significance level to support the claim that t its deluxe tire averages at least 50,000 miles before it needs to be replaced.
Answer:
6 =t
Step-by-step explanation:
-9 (t – 2) = 4(t – 15)
Distribute
-9t +18 = 4t -60
Add 9t to each side
-9t +18+9t = 4t+9t -60
18 = 13t -60
Add 60 to each side
18+60 = 13t-60+60
78 = 13t
Divide each side by 13
78/13 = 13t/13
6 =t
Answer:
4.8278117e+22
Step-by-step explanation:
Trial and error
tried 8 x 6 =48
i used 10 x 5 to get closer to 100
10 x 5= 50
50+ 48= 98 all I need is 6 which is 2 x 3
8 x 6 = 48
5 x 10= 50
3 x 2 = 6
Total = 104
Hope this helps