Given:
The rate of interest on three accounts are 7%, 8%, 9%.
She has twice as much money invested at 8% as she does in 7%.
She has three times as much at 9% as she has at 7%.
Total interest for the year is $150.
To find:
Amount invested on each rate.
Solution:
Let x be the amount invested at 7%. Then,
The amount invested at 8% = 2x
The amount invested at 9% = 3x
Total interest for the year is $150.
Multiply both sides by 100.
Divide both sides by 50.
The amount invested at 7% is .
The amount invested at 8% is
The amount invested at 9% is
Thus, the stockbroker invested $300 at 7%, $600 at 8%, and $900 at 9%.
Answer:
$23.41
Step-by-step explanation:
Add the cost of each item together.
$9.95 + $13.46 = $23.41
And there may have been sales tax as well but this information was not provided so it is not needed in the answer.
Cos(35) = x/6
or 6 * cos(35) = x
bearing in mind that the an hour has 15 + 15 + 15 + 15 = 60 minutes, so 15 minutes in 1/4 of an hour, thus 45 minutes is 3/4 of an hour.
now, from 11PM, if we add the 5 hours first, we'll be at 4AM, pass midnight of course.
now let's add the minutes, 32 and then 45, that gives us 77 minutes.
so the time will be 4AM plus 77 minutes, since 60 minutes is 1 hr, so 4AM plus 1 hr and 17 minutes, that'd be 5:17AM.
Answer:
38 divided by 16146.2 = 0.0023534949 then rounded to the nearest hundredth = 0.00
38. divided by 16146.2= The same as that one ^
1614.62 divided by 3.8= 424.9 then rounded you get 424.90