All categories

2 years ago

Triangle Review 2.0 (Math i need help please)

Mathematics

1 answer:

lara31 [8.8K]2 years ago

6 0

Answer:

A= 30

Step-by-step explanation:

This requires several steps.

First, you need to find the 2 other missing angles.

One can be found easily by substracting 130 from 180

so 180-130 = 50

The other angle is the same as 8x+4

Now set up your equation

180=3x-6 + 8x+4 +50

180 = 3x + 8x -6 + 4 +50

180+6-4-50 = 11x

132 = 11x

132/11 = x

12 = x

Now plug in 12 for x in your angle A

A=3x-6

A=3 * 12 - 6

A=36 - 6

A= 30

You might be interested in

F(x)=5-1/5x What are the x and y intercepts?

Bogdan [553]

Answer:

X intercepts 1/25=0

Y intercepts none

3 0

2 years ago

Triangle ABC Triangle DFE. What is the measure of Angle E in degrees?

Bas_tet [7]

Answer:

Angle E is 30⁰

Explanation:

If triangle ABC= triangle DFE then they are both the same it's just that in this case the triangles are mirrored meaning that Angle C= Angle E

Making Angle E: 30⁰

5 0

2 years ago

What is the surface area in centimeters of a cube with a side lengths of 1/8 centimeters

ipn [44]

Answer:

1/8 cm = 0.125 cm = 1.25 mm

6 * (1.25 mm)^2 = 9.375 mm^2

4 0

2 years ago

Read 2 more answers

A city council consists of seven Democrats and five Republicans. If a committee of four people is selected, find the probability

Hoochie [10]

Answer:

The probability of selecting two Democrats and two Republicans is 0.4242.

Step-by-step explanation:

The information provided is as follows:

A city council consists of seven Democrats and five Republicans.
A committee of four people is selected.

In mathematics, the procedure to select k items from n distinct items, without replacement, is known as combinations.

The formula to compute the combinations of k items from n is given by the formula:

${n\choose k}=\frac{n!}{k!\times (n-k)!}$

Compute the number of ways to select four people as follows:

${12\choose 4}=\frac{12!}{4!\times (12-4)!}=495$

Compute the number of ways to selected two Democrats as follows:

${7\choose 2}=\frac{7!}{2!\times (7-2)!}=21$

Compute the number of ways to selected two Republicans as follows:

${5\choose 2}=\frac{5!}{2!\times (5-2)!}=10$

Then the probability of selecting two Democrats and two Republicans as follows:

$P(\text{2 Democrats and 2 Republicans})=\frac{21\times 10}{495}=0.4242$

Thus, the probability of selecting two Democrats and two Republicans is 0.4242.

6 0

2 years ago

7x = -67 - 11v<br> 5x = -73 - 11v

Burka [1]

Answer:

x = 3, v = -8

Step-by-step explanation:

Substitute x.

$\frac{-67-11v}{7}$

[5 • $\frac{-67-11v}{7}$ = -73 - 11v]

Isolate v.

5 $\frac{-67-11v}{7}$ = -73 - 11v

v = -8

Substitute v.

x = $\frac{-67-11(-8)}{7}$

x = 3

4 0

2 years ago