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2 years ago

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Larissa starts with $250 and spends $25 a week. Chucho starts with $30 and saves $30 a week. Use x for time and y for savings. C

omplete the equation below to represent each situation.
Larissa: y = 250 - _____

1 answer:

Afina-wow [57]2 years ago

8 0

Answer: 25x

Step-by-step explanation:

y = 250 - 25x

(where y is total amount of money and x is number of weeks)

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Please answer this question for 25 points !!!

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Answer:548

Step-by-step explanation:

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2 years ago

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Mkey [24]

1. this is a series of squares Formula is an = n^2

2. Arithmetic series with common difference d = -2.

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2 years ago

3m=2(4+x) solve for x

algol13

Simple.........

3m=2(4+x)

Simplify...

3m=2(4+x)

3m=8+2x

Isolate the variable....

3m=8+2x
-8 -8

3m-8=2x

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Find the real zeros of the trigonometric function on the interval 0 ≤ x < 2π

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3 years ago

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Simplify. Can you explain it also?

Doss [256]

Answer:

The answer is

<h2> $\frac{3c}{4e}$ </h2>

Step-by-step explanation:

<h3> $\frac{9 {c}^{3}d {e}^{2} }{12 {c}^{2} d {e}^{3} }$ </h3>

To solve the fraction reduce the fraction with d

That's we have

<h2> $\frac{9 {c}^{3} {e}^{2} }{12 {c}^{2} {e}^{3} }$ </h2>

Next simplify the expression using the rules of indices to simplify the letters in the fraction

<u>For c </u>

Since they are dividing we subtract the exponents

We have

<h2> ${c}^{3} \div {c}^{2} = {c}^{3 - 2} = c^{1} = c$ </h2>

<u>For </u><u>e</u>

<h2> $e^{2} \div {e}^{3} = e^{2 - 3} = {e}^{ - 1} = \frac{1}{e}$ </h2>

Substituting them into the expression we have

<h2> $\frac{9c}{12e}$ </h2>

Reduce the fraction by 3

We have the final answer as

<h2> $\frac{3c}{4e}$ </h2>

Hope this helps you

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2 years ago