Let's assume the frequency of sound be f and wave length is w.
Given that, the frequency of sound varies inversely as the wavelength.
So, we can set up an equation as following:
f*w = k Where k= constant of variation.
Other information is, the frequency of a musical note is 276 cycles per second when the wavelength is 1.2m.
So, next step is to plug in f = 276 and w = 1.2 in the above equation to get the value of k.
276 * 1.2 = k
So, k = 331.2
Next step is to plug in k = 331.2 in the above equation. So,
f * w = 331.2
Now we need to find the wave length : w when frequency : f = 600.
Therefore,
600 * w = 331.2
So, w = 0.552
Hence, the wave length is 0.552 m.
Hope this helps you!.
Refrection of point (0, 0) across y = 3 gives point (0, 6)
Refrection of point (0, -6) across the x-axis gives point (0, -6)
Answer: Both families were travelling at the same speed/rate of 1mile/0.65mins or 1mile/0.01hr.
Step-by-step explanation: Speed of Houck family's train = 552m/6hrs
speed of Robert family's train = 744m/8hrs.
Therefore considering Houck speed,
552miles = 6hours
1mile = (6 x 60)/552
= 360/552
= 0.65minutes. Average speed = 1mile/0.65mins. Or 1mile/0.01hr
For Robert
744miles = 8hours
1mile = ( 8 x 60 )/744
= (480/744)minutes
= 0.645
= 0.65minutes. Average speed = 1mile/0.65mins. Or 1mile/0.01hr
Conclusion: Both families were travelling at the same speed/rate.
To get that minutes in hour, just divide by 60 to get concert to hours.
The question requires that the four lines that intersect form a parallelogram but not an specific parallelogram, so you are not restricted by a diagram.
You can use these equations for the four lines:
1) y = 0 (it is the x-axis)
2) y = 4 (it is a line parallel to the x-axis, whose y-intercept is 4.
3) y = x (it is an inclined line that intersects both y = 0 and y = 4 lines.
4) y = x + 7 (it is a line parallel to y = x, that also intersect the both y = 0 and y = 4 lines.
Given :
Xinran walks 3 mi/h uphill, 4 mi/h on flat land and 5 mi/h downhill.
To Find :
If he walks one mile uphill, then one mile on flat land and then returns by the same route to his starting point, how many minutes does he walk.
Solution :
Time taken to walk one mile uphill is :
Time taken to walk two mile on flat land( one on going and one or returning ) is :
Time taken to walk one mile downhill is :
Total time taken :
Therefore, time taken un 62 minutes.